Persamaan garis lurus yang melalui A(-2,5) dan bergradien 3/2 adalah…. *
2 poin
a. 2x – 3y + 16 = 0
b. 2x + 3y – 10 = 0
c. 3x – 2y + 16 = 0
d. 3x – 2y – 6 = 0
2 poin
a. 2x – 3y + 16 = 0
b. 2x + 3y – 10 = 0
c. 3x – 2y + 16 = 0
d. 3x – 2y – 6 = 0
Penjelasan dengan langkah-langkah:
y - y1 = m(x - x1)
y - 5 = 3/2(x + 2)
y - 5 = 3/2x + 3
y = 3/2x + 3 + 5
y = 3/2x + 8
y - 3/2x - 8 = 0
2y - 3x - 16 = 0
-3x + 2y - 16 = 0
3x - 2y + 16 = 0
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