Jawaban:
[tex]\large{\boxed{\sf{\sum\limits^{6}_{x=1} {(x^2-3)} = ...}}}[/tex]
penyelesaian :
[tex] \tt( {1}^{2} - 3) + ( {2}^{2} - 3) + ( {3}^{2} - 3) + ( {4}^{2} - 3) + ( {5}^{2} - 3) + ( {6}^{2} - 3)[/tex]
[tex] \tt(1 - 3) + (4 - 3) + (9 - 3) + (16 - 3) + (25 - 3) + (36 - 3)[/tex]
[tex] \tt( - 2) + 1 + 6 + 13 + 22 + 33[/tex]
[tex] \tt( -1 ) + 6 + 13 + 22 + 33[/tex]
[tex] \tt5 + 13 + 22 + 33[/tex]
[tex] \tt18 + 22 + 33[/tex]
[tex] \tt40 + 33[/tex]
[tex] \boxed{ \color{red} \tt = 73}[/tex]
Penjelasan dengan langkah-langkah:
[tex]\large{\boxed{\sf{\sum\limits^{6}_{x=1} {(x^2-3)} = ...}}}[/tex]
dijawab:
= (1²-3) + (2²-3)+(3²-3)+(4²-3)+(5²-3)+(6²-3)
= (1-3) + (4-3) + (9-3) + (16-3) + (25-3) + (36-3)
= (-2) + 1 + 6 + 13 + 22 + 33
= (-1) + 6 + 13 + 22 + 33
= 5 + 13 + 22 + 33
= 18 + 22 + 33
= 40 + 33
= 73
